Given an array with n objects colored red, white or blue, sort them so that objects of the same color
are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note:
You are not suppose to use the library's sort function for this problem.
Follow up:
A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of
0's, then 1's and followed by 2's.
Could you come up with an one-pass algorithm using only constant space?
1
这个可以用快排的三向切分的方法解决。
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public void sortColors(int[] nums) {
if(nums == null || nums.length < 2) return;
int lt = 0;
int i = 0;
int gt = nums.length-1;
int v = 1;
while( i <= gt){
if(nums[i] < v) swap(nums,lt++,i++);
else if(nums[i] > v) swap(nums,gt--,i);
else i++;
}
}
public void swap(int[] a,int i,int j){
if(i == j) return;
if(a[i] == a[j] ) return;
a[i] ^= a[j];
a[j] ^= a[i];
a[i] ^= a[j];
}
2
discuss most votes 也是这个答案。